jacobi_solve
std.linalg.jacobi_solve · Level L3Solve A·x = b by Jacobi iteration for a diagonally dominant A, from x = 0 until the relative residual is below 10⁻¹⁰. The diagonal comes from an Iota mask; the loop is a While.
Signature
jacobi_solve(A: f64[k, k], b: f64[k]) → f64[k]
Structure
The function as NOVA stores it: one box per input, operation and output, and arrows that carry values. A double border marks another library function this one runs — called once, or by Scan once per element; select it to open that function.
- input
- operation
- constant
- call
- output
Verification
- Signature proven by NOVA’s shape solver, for every size.
- Equal to the reference
x = 0; while ||b - A@x||^2 > 1e-20*||b||^2: x = (b - R@x) / diag(A)in exact rational arithmetic, on all 40 test cases. - All 147 float64 results inside the running error bound; the closest uses 28% of it.
- Interpreter and NumPy backend return bit-identical results.
- correctly rounded (the float64 nearest the exact value)
- 64%
- bit-equal to the NumPy formula in float64
- 100%
- largest error, in units in the last place
- 12
Large ulp counts appear where a result is zero or tiny next to the numbers it is computed from (after cancellation, for example), so one unit in the last place is tiny too; the absolute error is still inside the bound.
Note
Jacobi converges when each diagonal entry outweighs the rest of its row; the test matrices make it twice their sum, so the error at least halves every step.
Identity
sha256:5f7f8f1c8e4507d383aa84a5fe876365b2b6862f1b7702dab1c18784933da0e5The semantic hash of the graph. It changes when the program changes, and never when only its documentation does.